5 Percentage Increase Problems
5 Percentage Increase Problems
- Percentage Increase:
New Value = Original Value × (1 + Increase%/100)
Increase = Original Value × (Increase%/100)
Percentage Increase = [(New Value - Original Value) / Original Value] × 100 - Percentage Decrease:
New Value = Original Value × (1 - Decrease%/100)
Decrease = Original Value × (Decrease%/100)
Percentage Decrease = [(Original Value - New Value) / Original Value] × 100
Percentage Increase Problems
Problem 1: Price Increase
Problem: The price of a book is $50. If the price increases by 20%, find the new price.
Solution:
- Identify the given values:
- Original Price = $50
- Percentage Increase = 20%
- Calculate New Price:
- New Price = Original Price × (1 + Increase%/100)
- New Price = 50 × (1 + 20/100)
- New Price = 50 × 1.2 = $60
Answer:
- New Price = $60
Explanation:
- A percentage increase adds a fraction of the original value to itself.
- The multiplier (1 + Increase%/100) accounts for the original value plus the increase.
Problem 2: Population Growth
Problem: A town’s population is 10,000. It increases by 5% annually. Find the population after 1 year.
Solution:
- Identify the given values:
- Original Population = 10,000
- Percentage Increase = 5%
- Calculate New Population:
- New Population = Original Population × (1 + Increase%/100)
- New Population = 10,000 × (1 + 5/100)
- New Population = 10,000 × 1.05 = 10,500
Answer:
- New Population = 10,500
Explanation:
- The population grows by 5% of its original size, calculated using the percentage increase formula.
- The result is the new population after one year.
Problem 3: Salary Increase
Problem: An employee’s salary is $2000 per month. If it increases by 15%, find the new salary.
Solution:
- Identify the given values:
- Original Salary = $2000
- Percentage Increase = 15%
- Calculate New Salary:
- New Salary = Original Salary × (1 + Increase%/100)
- New Salary = 2000 × (1 + 15/100)
- New Salary = 2000 × 1.15 = $2300
Answer:
- New Salary = $2300
Explanation:
- The salary increase is calculated by multiplying the original salary by (1 + Increase%/100).
- This gives the new salary after the raise.
Problem 4: Find Original Value
Problem: After a 25% increase, the price of a gadget is $125. Find the original price.
Solution:
- Identify the given values:
- New Price = $125
- Percentage Increase = 25%
- Relate New Price to Original Price:
- New Price = Original Price × (1 + Increase%/100)
- 125 = Original Price × (1 + 25/100)
- 125 = Original Price × 1.25
- Solve for Original Price:
- Original Price = 125 / 1.25
- Original Price = $100
Answer:
- Original Price = $100
Explanation:
- The new price is 125% of the original price. Divide by 1.25 to find the original price.
- This reverses the percentage increase.
Problem 5: Calculate Percentage Increase
Problem: The price of a car increased from $20,000 to $22,000. Find the percentage increase.
Solution:
- Identify the given values:
- Original Price = $20,000
- New Price = $22,000
- Calculate Increase:
- Increase = New Price - Original Price
- Increase = 22,000 - 20,000 = $2000
- Calculate Percentage Increase:
- Percentage Increase = (Increase / Original Price) × 100
- Percentage Increase = (2000 / 20,000) × 100 = 10%
Answer:
- Percentage Increase = 10%
Explanation:
- The percentage increase is the increase divided by the original value, expressed as a percentage.
- This shows the relative change in price.
Problem 6: Successive Increases
Problem: A product’s price is $100. It increases by 10% in the first year and 20% in the second year. Find the final price.
Solution:
- Identify the given values:
- Original Price = $100
- First Increase = 10%
- Second Increase = 20%
- Calculate Price after First Increase:
- Price after first increase = 100 × (1 + 10/100)
- = 100 × 1.1 = $110
- Calculate Price after Second Increase:
- Final Price = 110 × (1 + 20/100)
- = 110 × 1.2 = $132
Alternative Method:
- Final Price = Original Price × (1 + First Increase%/100) × (1 + Second Increase%/100)
- = 100 × 1.1 × 1.2 = $132
Answer:
- Final Price = $132
Explanation:
- Successive percentage increases are applied sequentially, multiplying by each increase factor.
- The alternative method combines both increases in one step.
Problem 7: Increase to Match a Target
Problem: A shopkeeper wants to increase the price of an item from $80 to $100. Find the percentage increase required.
Solution:
- Identify the given values:
- Original Price = $80
- New Price = $100
- Calculate Increase:
- Increase = New Price - Original Price
- Increase = 100 - 80 = $20
- Calculate Percentage Increase:
- Percentage Increase = (Increase / Original Price) × 100
- Percentage Increase = (20 / 80) × 100 = 25%
Answer:
- Percentage Increase = 25%
Explanation:
- The percentage increase is calculated to determine how much the original price must rise to reach the target.
- The formula gives the relative increase needed.
Problem 8: Increase in Area
Problem: The side of a square is increased by 10%. Find the percentage increase in its area.
Solution:
- Identify the given values:
- Percentage Increase in Side = 10%
- Relate Side Increase to Area:
- Let original side = s
- Original Area = s²
- New Side = s × (1 + 10/100) = s × 1.1
- New Area = (1.1s)² = 1.21s²
- Calculate Percentage Increase in Area:
- Increase in Area = New Area - Original Area = 1.21s² - s² = 0.21s²
- Percentage Increase = (Increase / Original Area) × 100
- = (0.21s² / s²) × 100 = 21%
Answer:
- Percentage Increase in Area = 21%
Explanation:
- The area of a square is proportional to the square of its side. A 10% increase in side results in a (1.1)² = 1.21 factor increase in area.
- The percentage increase is calculated relative to the original area.
Problem 9: Increase with Fractional Percentage
Problem: A stock price of $200 increases by 7.5%. Find the new stock price.
Solution:
- Identify the given values:
- Original Price = $200
- Percentage Increase = 7.5%
- Calculate New Price:
- New Price = Original Price × (1 + Increase%/100)
- New Price = 200 × (1 + 7.5/100)
- New Price = 200 × 1.075 = $215
Answer:
- New Stock Price = $215
Explanation:
- Fractional percentages are handled the same way as whole percentages in the formula.
- The new price reflects the original price plus the increase.
Problem 10: Repeated Increase
Problem: A value of 100 increases by 5% each year for 2 years. Find the final value.
Solution:
- Identify the given values:
- Original Value = 100
- Percentage Increase per Year = 5%
- Time = 2 years
- Calculate Value after First Year:
- Value after Year 1 = 100 × (1 + 5/100)
- = 100 × 1.05 = 105
- Calculate Value after Second Year:
- Final Value = 105 × (1 + 5/100)
- = 105 × 1.05 = 110.25
Alternative Method:
- Final Value = Original Value × (1 + Increase%/100)^n
- = 100 × (1.05)^2
- = 100 × 1.1025 = 110.25
Answer:
- Final Value = 110.25
Explanation:
- Repeated percentage increases are compounded, similar to compound interest.
- The formula (1 + Increase%/100)^n accounts for multiple increases.
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