22. Problems involving addition

 22. Problems involving addition - step by step solution procedure and detailed explanation for each problem.

Problem 1: Adding Fractions
Problem: A recipe requires
\frac{1}{4}
cup of sugar for the cake and
\frac{3}{4}
cup for the frosting. How much sugar is needed in total?
Step-by-Step Solution:
  1. Identify the fractions:
    • Cake:
      \frac{1}{4}
    • Frosting:
      \frac{3}{4}
  2. Check the denominators:
    • Both have the same denominator (4).
  3. Add the numerators:
    • 1 + 3 = 4
      .
  4. Keep the denominator:
    • \frac{4}{4} = 1
      .
  5. Write the answer: The recipe needs 1 cup of sugar.
Detailed Explanation:
  • When adding fractions with the same denominator, add the numerators and keep the denominator.
  • Here,
    \frac{1}{4} + \frac{3}{4} = \frac{1+3}{4} = \frac{4}{4} = 1
    .
  • The result, 1 cup, is a whole number, indicating the total sugar required.

Problem 2: Adding Mixed Numbers
Problem: A carpenter cuts two pieces of wood: one is
2 \frac{1}{3}
feet and the other is
1 \frac{2}{3}
feet. What is the total length?
Step-by-Step Solution:
  1. Identify the mixed numbers:
    • First piece:
      2 \frac{1}{3}
    • Second piece:
      1 \frac{2}{3}
  2. Add the whole numbers:
    • 2 + 1 = 3
      .
  3. Add the fractions:
    • \frac{1}{3} + \frac{2}{3} = \frac{1+2}{3} = \frac{3}{3} = 1
      .
  4. Add the fraction result to the whole number:
    • 3 + 1 = 4
      .
  5. Write the answer: The total length is 4 feet.
Detailed Explanation:
  • Mixed numbers are added by separately handling the whole numbers and fractions.
  • The fractions have the same denominator, so add the numerators:
    \frac{1}{3} + \frac{2}{3} = \frac{3}{3} = 1
    .
  • This 1 is a whole number, which is added to the sum of the whole numbers (3), giving 4.
  • The result, 4 feet, is the total length of the wood.

Problem 3: Word Problem with Addition
Problem: A school collects 245 cans of food on Monday, 198 cans on Tuesday, and 312 cans on Wednesday. How many cans are collected in total?
Step-by-Step Solution:
  1. Identify the quantities:
    • Monday: 245 cans
    • Tuesday: 198 cans
    • Wednesday: 312 cans
  2. Set up the addition: ``` 245 +198 +312

  1. Add step-by-step:
    • First, add
      245 + 198
      :
      • Units:
        5 + 8 = 13
        , write 3, carry 1.
      • Tens:
        4 + 9 + 1 = 14
        , write 4, carry 1.
      • Hundreds:
        2 + 1 + 1 = 4
        .
      • Result: 443.
    • Then, add
      443 + 312
      :
      • Units:
        3 + 2 = 5
        .
      • Tens:
        4 + 1 = 5
        .
      • Hundreds:
        4 + 3 = 7
        .
      • Result: 755.
  2. Write the answer: The school collects 755 cans.
Detailed Explanation:
  • This problem involves adding three multi-digit numbers, which can be done by pairing numbers for simplicity.
  • Adding 245 and 198 gives 443, then adding 312 to 443 gives 755.
  • Vertical addition ensures accuracy by aligning place values.
  • The total, 755 cans, represents the sum of all collections.

Problem 10: Adding Negative Numbers
Problem: A submarine is at a depth of -150 meters. It ascends 75 meters and then descends 50 meters. What is its final depth?
Step-by-Step Solution:
  1. Identify the initial depth and changes:
    • Initial depth: -150 meters
    • Ascent: +75 meters (positive because it reduces depth)
    • Descent: -50 meters (negative because it increases depth)
  2. Set up the addition:
    • Final depth =
      -150 + 75 + (-50)
      .
  3. Add step-by-step:
    • First,
      -150 + 75
      :
      • -150 + 75 = -75
        (since 150 - 75 = 75, and the negative sign remains).
    • Then,
      -75 + (-50)
      :
      • -75 - 50 = -125
        .
  4. Write the answer: The final depth is -125 meters.
Detailed Explanation:
  • This problem involves adding integers, including negative numbers.
  • Ascending 75 meters reduces the depth, so it’s +75. Descending 50 meters increases the depth, so it’s -50.
  • Adding
    -150 + 75 = -75
    , then
    -75 - 50 = -125
    .
  • The final depth, -125 meters, indicates the submarine is 125 meters below sea level.


Comments

|

Blog Archive

Show more