22. Problems involving addition
22. Problems involving addition - step by step solution procedure and detailed explanation for each problem.
Problem 1: Adding Fractions
Problem: A recipe requires cup of sugar for the cake and cup for the frosting. How much sugar is needed in total?
\frac{1}{4}
\frac{3}{4}
Step-by-Step Solution:
- Identify the fractions:
- Cake:
\frac{1}{4}
- Frosting:
\frac{3}{4}
- Check the denominators:
- Both have the same denominator (4).
- Add the numerators:
- .
1 + 3 = 4
- Keep the denominator:
- .
\frac{4}{4} = 1
- Write the answer: The recipe needs 1 cup of sugar.
Detailed Explanation:
- When adding fractions with the same denominator, add the numerators and keep the denominator.
- Here,.
\frac{1}{4} + \frac{3}{4} = \frac{1+3}{4} = \frac{4}{4} = 1
- The result, 1 cup, is a whole number, indicating the total sugar required.
Problem 2: Adding Mixed Numbers
Problem: A carpenter cuts two pieces of wood: one is feet and the other is feet. What is the total length?
2 \frac{1}{3}
1 \frac{2}{3}
Step-by-Step Solution:
- Identify the mixed numbers:
- First piece:
2 \frac{1}{3}
- Second piece:
1 \frac{2}{3}
- Add the whole numbers:
- .
2 + 1 = 3
- Add the fractions:
- .
\frac{1}{3} + \frac{2}{3} = \frac{1+2}{3} = \frac{3}{3} = 1
- Add the fraction result to the whole number:
- .
3 + 1 = 4
- Write the answer: The total length is 4 feet.
Detailed Explanation:
- Mixed numbers are added by separately handling the whole numbers and fractions.
- The fractions have the same denominator, so add the numerators:.
\frac{1}{3} + \frac{2}{3} = \frac{3}{3} = 1
- This 1 is a whole number, which is added to the sum of the whole numbers (3), giving 4.
- The result, 4 feet, is the total length of the wood.
Problem 3: Word Problem with Addition
Problem: A school collects 245 cans of food on Monday, 198 cans on Tuesday, and 312 cans on Wednesday. How many cans are collected in total?
Step-by-Step Solution:
- Identify the quantities:
- Monday: 245 cans
- Tuesday: 198 cans
- Wednesday: 312 cans
- Set up the addition: ``` 245 +198 +312
- Add step-by-step:
- First, add:
245 + 198
- Units:, write 3, carry 1.
5 + 8 = 13
- Tens:, write 4, carry 1.
4 + 9 + 1 = 14
- Hundreds:.
2 + 1 + 1 = 4
- Result: 443.
- Then, add:
443 + 312
- Units:.
3 + 2 = 5
- Tens:.
4 + 1 = 5
- Hundreds:.
4 + 3 = 7
- Result: 755.
- Write the answer: The school collects 755 cans.
Detailed Explanation:
- This problem involves adding three multi-digit numbers, which can be done by pairing numbers for simplicity.
- Adding 245 and 198 gives 443, then adding 312 to 443 gives 755.
- Vertical addition ensures accuracy by aligning place values.
- The total, 755 cans, represents the sum of all collections.
Problem 10: Adding Negative Numbers
Problem: A submarine is at a depth of -150 meters. It ascends 75 meters and then descends 50 meters. What is its final depth?
Step-by-Step Solution:
- Identify the initial depth and changes:
- Initial depth: -150 meters
- Ascent: +75 meters (positive because it reduces depth)
- Descent: -50 meters (negative because it increases depth)
- Set up the addition:
- Final depth =.
-150 + 75 + (-50)
- Add step-by-step:
- First,:
-150 + 75
- (since 150 - 75 = 75, and the negative sign remains).
-150 + 75 = -75
- Then,:
-75 + (-50)
- .
-75 - 50 = -125
- Write the answer: The final depth is -125 meters.
Detailed Explanation:
- This problem involves adding integers, including negative numbers.
- Ascending 75 meters reduces the depth, so it’s +75. Descending 50 meters increases the depth, so it’s -50.
- Adding, then
-150 + 75 = -75
.-75 - 50 = -125
- The final depth, -125 meters, indicates the submarine is 125 meters below sea level.
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