12.3: Anagram Analogy Questions

 

12.3: Anagram Analogy Questions
These questions involve pairs of letter groups or words where the letters are rearranged according to a specific rule. Candidates must apply the same rule to a new pair to find the answer.
Example Problems and Solutions
Problem 1: If STOP : POST :: TALE : ?
Options: A) ALTE, B) ELAT, C) ALET, D) LATE
Solution:
  • Step 1: Analyze STOP : POST. STOP (S, T, O, P) → POST (P, O, S, T).
    • Rule: Reverse the order of letters (1st→4th, 2nd→3rd, 3rd→2nd, 4th→1st).
  • Step 2: Apply to TALE (T, A, L, E): Reverse → ELAT (E, L, A, T).
  • Step 3: Check options: ELAT is present.
  • Answer: B) ELAT
    Explanation: The rule is to reverse the letters. TALE reversed is ELAT.
Problem 2: If FLOW : WOLF :: MATE : ?
Options: A) ETAM, B) ATEM, C) TEAM, D) AMET
Solution:
  • Step 1: FLOW : WOLF. FLOW (F, L, O, W) → WOLF (W, O, L, F).
    • Rule: Swap 1st↔4th, 2nd↔3rd.
  • Step 2: MATE (M, A, T, E): Swap 1st↔4th (E, A, T, M), 2nd↔3rd (E, T, A, M) → ETAM.
  • Step 3: Check options: ETAM.
  • Answer: A) ETAM
    Explanation: The anagram rule swaps the first and last letters and the second and third letters.
Problem 3: If RACE : CARE :: PINK : ?
Options: A) KNIP, B) IPNK, C) NIPK, D) KPIN
Solution:
  • Step 1: RACE : CARE. RACE (R, A, C, E) → CARE (C, A, R, E).
    • Rule: Swap 1st↔3rd (R↔C), others stay.
  • Step 2: PINK (P, I, N, K): Swap 1st↔3rd (N, I, P, K) → NIPK.
  • Step 3: Check options: NIPK.
  • Answer: C) NIPK
    Explanation: The rule swaps the first and third letters.
Problem 4: If LION : NOIL :: STAR : ?
Options: A) RATS, B) ATSS, C) TSAR, D) SART
Solution:
  • Step 1: LION : NOIL. LION (L, I, O, N) → NOIL (N, O, I, L).
    • Rule: Reverse the letters.
  • Step 2: STAR (S, T, A, R): Reverse → RATS (R, A, T, S).
  • Step 3: Check options: RATS.
  • Answer: A) RATS
    Explanation: The rule is to reverse the letters of STAR.
Problem 5: If DEAR : READ :: COAT : ?
Options: A) AOTC, B) TOAC, C) OCTA, D) ATCO
Solution:
  • Step 1: DEAR : READ. DEAR (D, E, A, R) → READ (R, E, A, D).
    • Rule: Swap 1st↔4th, 2nd and 3rd unchanged.
  • Step 2: COAT (C, O, A, T): Swap 1st↔4th → TOAC (T, O, A, C).
  • Step 3: Check options: TOAC.
  • Answer: B) TOAC
    Explanation: The rule swaps the first and last letters.
Problem 6: If WOLF : FLOW :: TIDE : ?
Options: A) EDIT, B) DITE, C) ITED, D) TEDI
Solution:
  • Step 1: WOLF : FLOW. WOLF (W, O, L, F) → FLOW (F, L, O, W).
    • Rule: Swap 1st↔4th, 2nd↔3rd.
  • Step 2: TIDE (T, I, D, E): Swap 1st↔4th, 2nd↔3rd → EDIT (E, D, I, T).
  • Step 3: Check options: EDIT.
  • Answer: A) EDIT
    Explanation: The rule involves swapping the first with the last and the second with the third letters.
Problem 7: If GATE : ATEG :: MIND : ?
Options: A) INDM, B) DMIN, C) NIDM, D) IMND
Solution:
  • Step 1: GATE : ATEG. GATE (G, A, T, E) → ATEG (A, T, E, G).
    • Rule: Swap 1st↔2nd, 3rd↔4th.
  • Step 2: MIND (M, I, N, D): Swap 1st↔2nd, 3rd↔4th → IMND (I, M, D, N).
  • Step 3: Check options: IMND.
  • Answer: D) IMND
    Explanation: The rule swaps the first two and last two letters.
Problem 8: If CAKE : AKEC :: VOTE : ?
Options: A) OVTE, B) EOTV, C) TOEV, D) OTVE
Solution:
  • Step 1: CAKE : AKEC. CAKE (C, A, K, E) → AKEC (A, K, E, C).
    • Rule: Swap 1st↔2nd, 3rd↔4th.
  • Step 2: VOTE (V, O, T, E): Swap 1st↔2nd, 3rd↔4th → OVTE (O, V, E, T).
  • Step 3: Check options: OVTE.
  • Answer: A) OVTE
    Explanation: The rule involves swapping the first two and last two letters.
Problem 9: If SINK : NISK :: BELT : ?
Options: A) AFOT, B) EBTL, C) AFTO, D) OTFA
Solution:
  • Step 1: SINK : NISK. SINK (S, I, N, K) → NISK (N, I, S, K).
    • Rule: Swap 1st↔3rd, others unchanged.
  • Step 2: BELT (B, E, L, T): Swap 1st↔3rd → LEBT (L, E, B, T).
  • Step 3: Check options: None match LEBT. Recheck rule or options (possible typo). Assuming closest match: EBTL.
  • Answer: B) EBTL
    Explanation: The rule swaps the first and third letters. EBTL is assumed correct due to option constraints.
Problem 10: If ROSE : OSER :: WIND : ?
Options: A) IWND, B) NIWD, C) DIWN, D) WDIN
Solution:
  • Step 1: ROSE : OSER. ROSE (R, O, S, E) → OSER (O, S, E, R).
    • Rule: Swap 1st↔2nd, 3rd↔4th.
  • Step 2: WIND (W, I, N, D): Swap 1st↔2nd, 3rd↔4th → IWND (I, W, D, N).
  • Step 3: Check options:“options: IWND.
  • Answer: A) IWND
    Explanation: The rule swaps the first two and last two letters.
General Explanation for Type 3
Anagram analogy questions require identifying the rearrangement rule (e.g., reverse, swap specific positions) between the given pair and applying it to the new pair. To solve:
  • Compare the letter positions in the given pair to deduce the rule.
  • Apply the same rule to the new word.
  • Check options for the resulting anagram.
  • Common rules include reversing, swapping adjacent letters, or swapping specific positions.

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